問題詳情
10. 如右圖所示之電路圖,Vs = 2∠0°V,ω = 106 rad/s,R1 = 5 kΩ,R2 = 100 kΩ,R3= 20 kΩ,C1 = 0.1 nF,C2 = 0.01 nF,請問 Vo值為何?
(A) V
o = 7.56cos(106t + 79.09°) V
(B) Vo = 8.46cos(106t + 36.17° )V
(C) Vo = 9.26cos(106t + 53.16° ) V
(D) Vo = 10.87cos(106t + 45°) V
參考答案
答案:A
難度:計算中-1
書單:沒有書單,新增