問題詳情
14. A man and woman are each heterozygous for the autosomal recessive disorder cystic fibrosis. If they wantto have three children, what is the probability that only one of the children will have cystic fibrosis?
(A) 1/4
(B) 3/4
(C) 9/16
(D)9/64
(E)27/64
參考答案
答案：[無官方正解]
難度：計算中-1
書單：沒有書單，新增
用户評論
【面試倒楣鬼-22幸運上後西】評論
體染色體隱性 >= Cc * Cc =(1/4)*(3/4)*(3/4) *C3取1 = 27/64 (E)