【陳鈺宗(Chen Yu Z】評論
D
【林鯨魚】評論
tan(β+γ)=(tanβ+tanγ)/(1-tanβ x tanγ)=(1/5+1/8)/(1-1/5x1/8)=(13/40)/(39/40)=1/3tan(α+β+γ)=(tanα+tan(β+γ))/(1-tanα x tan(β+γ))=(1/2+1/3)/(1-1/2 x 1/3)=(5/6)/(5/6)=1