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• 43.有以下程序 main() { unsigned int a; int b=-1; a=b; printf("%u",A); } 程序运行后的输出结
• AOnly three local students won Chinese Blog（博客）Competition. And 15 of the 18 awards want to students
• 【題組】51. (A) trouble (B) gift (C) fact (D) trick Ks5u
• 29.若有以下说明和语句，int c[4][5],(*p)[5];p=c;能正确引用c数组元素的是(A)p+1 (B)*(p+3)(C)*(p+1)+3 (D)*(p[0]+2])
• 37.在函数调用过程中，如果函数funA调用了函数 funB,函数funB又调用了函数funA，则 (A)称为函数的直接递归调用 (B)称为函数的间接递归调用 (C)称为函数的循环调用 (D)C
• 44.有以下程序 void fun(int *a,int i,int j) { int t; if(i<J)  { t=a;a=a[j];a[j]=t;  i++; j--;
• 【題組】57. Which of the following is TRUE according to the passage?(A) Chinese students won most of the
• 【題組】52. (A) perform (B) write (C) hear (D) question Ks5u
• 【題組】45. (A) talked about (B) cared about (C) wrote about (D) heard about
• 30.有以下程序 main() { int a=7,b=8,*p,*q,*r; p=&a;q=&b; r=p; p=q;q=r; printf("%d,%d,%d,%dn
• 45.有以下说明和定义语句 struct student { int age; char num[8];}; struct student stu[3]={{20,"200401
• 【題組】58. What Miss Gao said suggests that(A) she likes to blame the authorities (B) she has a sense o
• 【題組】53. (A) means (B) ends (C) begins (D) proves Ks5u
• 38.已有定义：int i,a[10],*p;,则合法的赋值语句是 (A)p=100; (B)p=a[5]; (C)p=a[2]+2; (D)p=a+2;
• 31.s12和s2已正确定义并分别指向两个字符串。若要求：当s1所指串大于s2所指串时，执行语句S;则以下选项中正确的是 (A)if(s1>s2)S; (B)if(strcmp(s1,s2)
• 【題組】47. (A) beyond (B) over (C) behind (D) through
• 48.48~50.以下程序的功能是：建立一个带有头结点的单向链表，并将存储在数组中的 字符依次转储到链表的各个结点中，请从与下划线处号码对应的一组选若中选择出 正确的选项。 #includ
• 【題組】59. The passage in mainly about(A) how Chinese students won the awards in the competition(B) why
• 39.以下叙述中正确的是(A)局部变量说明为static存储数，其生存期将得到延长(B)全局变量说明为static存储类，其作用域将被扩大(C)任何存储类的变量在未赋初值时，其值都是不确定的(D)形参
• 49.(A)*s (B)s (C)*s++ (D)(*s)++
• BForeign drivers will have a pay on-the-spot fines of up to ￡900 for breaking the traffic law to be
• 33.有以下程序 #include main() {int a[]={1,2,3,4,5,6,7,8,9,10,11,12,},*p=a+5,*q=NULL; *q=*(p+5);
• 【題組】49. (A) study (B) design (C) committee (D) staff
• 40.设有定义语句：char c1=92,c2=92;,则以下表达式中值为零的是 (A)c1^c2 (B)c1&c2 (C)~c2 (D)c1|c2
• 50.(A)p->next (B)p (C)s (D)s->next