問題詳情
10. CH3COOH(aq)+H2O(I)→H3O+(aq)+CH3COO-(aq),whichdescriptionis incorrect?
(A)Ka = [H3O+] [CH3COO-]/[CH3COOH]
(B) pH = logKa
(C)H3O+ is the conjugate base to CH3COOH.
(D) The Ka value of CH3COOH is 1.7 x 10-5, indicating it's a kind of weak acids.
(E) pKa = 4.76