【用戶】boy789q
【年級】小二上
【評論內容】(1)IC(sat)= Vcc / Rc = 0.5maIB=Vcc-Vbe / Rb = 10-0.7 / 372k =0.025mAIC = B* IB = 100*0.025MA = 2.5 mAVce = Vcc - IcRc = 10 - 2.5mA * 2k = 5V (2)Rb 開路開路後 Vcc = Vce = 10Vdc(3) Rb = 100kIB = Vcc-Vbe /Rb = 10-0.7 / 100k =0.093mAIC = B * IB = 100* 0.093 = 9.3ma 飽和故Vce(sat) = 0.2V