問題詳情
(8)Given average kinetic energy, (K) =

(kT), of a molecule in air at room temperature (20°C = 293K), please determine the root-mean-square speed of an O2 molecule with this energy. (k = 1.38×10⁻²³ J/K, 1u = 1.66×10⁻²⁷ kg)
(A)511 m/s
(B)671 m/s
(C)478 m/s
(D)823 m/s
(E)379 m/s
參考答案
答案:C
統計:A:0,B:0,C:0,D:0,E:0
難度:計算中