4向量a=[1,2,3],向量b=[-4,-5,-6],設兩向量之夾角為θ,則cosθ = ?(A)
【電子荔枝】評論
內積a·b = |a| |b| cosθ = a1b1+a2b2+a3b3|a| = √ (12+22+32) = √14|b| = √77cosθ = -32/√14 √77 = -16√22/77