17. From the abbreviated name of the compound Gal(β1→4)Glc, we know that:
(A) C-4 of glucose is joined to C-1 of galactose by a glycosidic bond.
(B) the compound is a D-enantiomer.
(C) the galactose residue is at the reducing end.
(D) the glucose is in its pyranose form.
(E) the glucose residue is the β anomer.
答案：99
統計：A:0,B:0,C:0,D:0,E:0
難度：計算中