問題詳情
23.艾克曼(Ackerman)遞迴函數之定義如下：
(A) 3
(B) 6
(C) 9
(D) 12
(A) 3
(B) 6
(C) 9
(D) 12
參考答案
答案：C
難度：適中0.444444
統計：A(1),B(1),C(4),D(1),E(0)
難度：適中0.444444
統計：A(1),B(1),C(4),D(1),E(0)
用户評論
【安身立命】評論
a(2,3)=a(1,a(2,2))a(2,2)=a(1,a(2,1))a(2,1)=a(1,a(2,0))a(2,0)=a(1,1)a(1,1)=a(0,a(1,0))a(1,0)=a(0,1)a(0,1)=2a(0,2)=3a(1,3)=a(0,a(1,2))a(1,2)=a(0,a(1,1))a(1,1)=a(0,a(1,0))a(1,0)=a(0,1)a(0,1)=2a(0,2)=3a(0,3)=4a(0,4)=5a(1,5)=a(0,a(1,4))a(1,4)=a(0,a(1,3))a(1,3)=a(0,a(1,2))a(1,2)=a(0,a(1,1))a(1,1)=a(0,a(1,0))a(1,0)=a(0,1)a(0,1)=2a(0,2)=3a(0,3)=4a(0,4)=5a(0,5)=6a(0,6)=7a(1,7)=a(0,a(1,6))a(1,6)=a(0,a(1,5))a(1,5)=a(0,a(1,4))a(1,4)=a(0,a(1,3))a(1,3)=a(0,a(1,2))a(1,2)=a(0,a(1,1))a(1,1)=a(0,a(1,0))a(1,0)=a(0,1)a(0,1)=2a(0,2)=3a(0,3...