問題詳情

32. 某船由甲地（Lat 25°10.3'N，λ 121°44.9'E）以航向070°航行246浬，求中緯航法之到達點的經緯度為何？
(A) 26°29.4'N；124°53.3'E
(B) 26°29.4'N；125°15.4'E
(C) 26°34.4'N；124°53.5'E
(D) 26°34.4'N；126°01.8'E

參考答案

答案：D
難度：困難0.325
書單：沒有書單，新增

用户評論

【小楓葉】評論

070 = N70EDL = 246 * COS70 = 84.13 = 1°24.8'P = 246 * SIN70 = 231.16L1+ DL=  L2 L1   25°10.3'  + DL 1°24.8'  =  L2  26°34.11' ☆(L1+ L2 )/2= Lm(L1   25°10.3 '+ L2  26°34.11') / 2= Lm 25°52.7'Dλ = P /  cos Lm231.16 / cos 25°52.7' = 256.9 = 4°16.54'λ 1+Dλ = λ 2λ 121°44.9'+4°16.54' = 126°01.3' ☆  

【KYLE】評論

DL = 246 * COS70 = 84.14 = 1°24.14l2=25°10.3'N+1°24.14=26°34.4'Np=dxsincp=246 xsin70°p=231.16dλ =p/cos lmdλ =231.16/coslmlm=25°10.3'N+ 26°34.4'N=51°44.7=25.5°22.35=25°52.35dλ =231.16/cos25°52.35dλ =231.16/0.89977=256.91=4°16.91λ 121°44.9'E+4°16.91=126°01.81e