問題詳情

運動時的能量來源，以有氧能量系統來說，一分子的葡萄糖完全氧化可以產生多少ATP？
(A)2
(B)24
(C)38
(D)42。

參考答案

答案：C
難度：簡單0.744943
統計：A(61),B(134),C(847),D(29),E(0)

用户評論

【李健美】評論

有高手能解嗎?

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【李健美】評論

有高手能解嗎?

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP

【姜頂天】評論

糖解作用）4ATP-2ATP+2NADH丙酮酸氧化）2NADH檸檬酸循環）6NADH+2GTP+2FADH2<1NADH=3ATP;1FADH2=2ATP;1GTP=1ATP>10NADHx3+2FADH2x2+2ATP+2GTPx1=38ATP