問題詳情

34. Which one of the following is the characteristic of the glycerophosphate shuttle?
(A)It only operates efficiently when the [NADH] in the cytoplasm is higher than in the matrix.
(B) It shuttles "NADH electron equivalents" across the mitochondrial membrane to yield I.5ATP/NADH.
(C) It shuttles NADH across the mitochondrial membrane to yield 2.5 ATP /NADH
(D) Aspartate is a key component in the shuttle process.
(E) Malate is a key component in the shuttle process.

參考答案

答案:B
難度:計算中-1
書單:沒有書單,新增

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2 NADH from glycolysis糖解作用而來的2NADHglycerol 3-phosphate shuttle 或malate-aspartate shuttle*glycerol 3-phosphate shuttle:2 NADH × 1.5ATP或2ATP= 3或4ATP *malate-aspartate shuttle:2 NADH × 2.5ATP或3ATP= 5或6ATP *1 glucose:  →30ATP或36ATP(glycerol 3-phosphate shuttle): 腦、神經細胞、人類白肌  →32ATP或38ATP(malate-aspartate shuttle): 腎臟、心肌細胞、肝臟*葡萄糖完全氧化產生的 ATP 產量: ATP產生量Glycolysis糖解作用2 ATP2 NADH from glycolysis糖解作用而來的2NADHglycerol 3-phosphate shuttle 或malate-aspartate shuttle*glycerol 3-phosphate shuttle:2 NADH × 1.5ATP或2ATP= 3或4ATP *malate-aspartate shuttle:2 NADH × 2.5ATP或3ATP= 5或6ATP 2個pyruvatepyruvate dehydrogenase 產生2 NADH(2個pyruvate→2個acetyl CoA)2 NADH × 2.5ATP或3ATP= 5或6ATP TCA cycle2個Acetyl-CoAisocitrate dehydrogenase產生2 NADH(2個isocitrate→2個α-ketoglutarate)2 NADH × 2.5ATP或3ATP= 5或6ATP TCA cycle2個Acetyl-CoAα-ketoglutarate dehydrogenase產生2 NADH(2個α-ketoglutarate→2個succinyl CoA)2 NADH × 2.5ATP或3ATP= 5或6ATP TCA cycle2個Acetyl-CoAsuccinyl CoA synthetase=thiokinase產生2 GTP(2個succinyl CoA→2個succinate)2 GTP × 1ATP = 2 ATP TCA cycle2個Acetyl-CoAsuccinate dehydrogenase產生2 FADH2(2個succinate→2個fumarate)2 FADH2 × 1.5ATP或2ATP= 3或4ATP TCA cycle2個Acetyl-CoAmalate dehydrogenase產生2 NADH(2個malate→2個oxaloacetate)2 NADH × 2.5ATP或3ATP= 5或6ATP 葡萄糖完全氧化產生的 ATP 產量*glycerol 3-phosphate shuttle:*NADH以2.5ATP計算和FADH2以1.5ATP計算:2+3+5+5+5+2+3+5= 30ATP*NADH以3ATP計算和FADH2以2ATP計算:2+4+6+6+6+2+4+6= 36ATP    *malate-aspartate shuttle:*NADH以2.5ATP計算和FADH2以1.5ATP計算:2+5+5+5+5+2+3+5= 32ATP *NADH以3ATP計算和FADH2以2ATP計算:2+6+6+6+6+2+4+6= 38ATP  *1 acetyl CoA:→*NADH以2.5ATP計算和FADH2以1.5ATP計算:2.5+2.5+1+1.5+2.5=10ATP→*NADH以3ATP計算和FADH2以2ATP計算: 3+3+1+2+3=12ATP  *1 pyruvate:→*NADH以2.5ATP計算和FADH2以1.5ATP計算:2.5+2.5+2.5+1+1.5+2.5=12.5ATP→*NADH以3ATP計算和FADH2以2ATP計算: 3+3+3+1+2+3=15ATP