14.若 f(x)存在反函數f-1(x)且f (x) + f (-x) = 3，則 f-1(x-3)+f-1(6-x)=?(A) - 2 (B) -1 (C) 0 (D) 1

問題詳情

14.若 f(x)存在反函數f-1(x)且f (x) + f (-x) = 3，則 f-1(x-3)+f-1(6-x)=?
(A) - 2
(B) -1
(C) 0
(D) 1

參考答案

答案：C
難度：困難0.243243
統計：A(3),B(7),C(9),D(6),E(0)

用户評論

【蔡幸樺】評論

令 f^(-1)(x - 3) = a，f^(-1)(6 - x) = b則 f(a) + f(b) = x - 3 + 6 - x = 3又 f(a) + f(-a) = 3f(-a) = f(b) = 6 - x-a = f^(-1)(6 - x) = ba + b = 0