問題詳情

16A(2 , -4)﹐B(5 , -2)﹐求以

為直徑的圓方程式為何？
(A)x2 + y2 - 7x + 6y + 18 = 0
(B)x2 + y2 - 7x - 6y + 18 = 0
(C)x2 + y2 - 6x + 7y + 18 = 0
(D)x2 + y2 + 7x - 6y + 18 = 0
(E)x2 + y2 + x + y + 18 = 0﹒

參考答案

答案：A
難度：非常困難0
統計：A(0),B(0),C(0),D(0),E(0)

用户評論

【用戶】陳俊友

【年級】高三下

【評論內容】16. A(2 , -4)﹐B(5 , -2)﹐求以為直徑的圓方程式為何？(A)x2 + y2 - 7x + 6y + 18 = 0(B)x2 + y2 - 7x - 6y + 18 = 0(C)x2 + y2 - 6x + 7y + 18 = 0(D)x2 + y2 + 7x - 6y + 18 = 0(E)x2 + y2 + x + y + 18 = 0.

【用戶】【站僕】摩檸Morning

【年級】小一下

【評論內容】原本題目:16A(2 , -4)﹐B(5 , -2)﹐求以為直徑的圓方程式為何？ (A)x2 + y2 - 7x + 6y + 18 = 0 (B)x2 + y2 - 7x - 6y + 18 = 0 (C)x2 + y2 - 6x + 7y + 18 = 0 (D)x2 + y2 + 7x - 6y + 18 = 0 (E)x2 + y2 + x + y + 18 = 0﹒修改成為16A(2 , -4)﹐B(5 , -2)﹐求以為直徑的圓方程式為何？ (A)x2 + y2 - 7x + 6y + 18 = 0 (B)x2 + y2 - 7x - 6y + 18 = 0 (C)x2 + y2 - 6x + 7y + 18 = 0 (D)x2 + y2 + 7x - 6y + 18 = 0 (E)x2 + y2 + x + y + 18 = 0﹒...