【江戶川兩津】評論
pOH- : 5-log2 = 5-0.301 = 4.7pH= 14-pOH = 14-4.7 = 9.3
pOH- : 5-log2 = 5-0.301 = .....看完整詳解
【小Mye】評論
鹼解離方成式B+H2O=[BH+] +[OH-]Kb = [BH+][OH-]/[B],當B=H+,得OH-=KbpOH= 5-log2=4.7pH=14-.4.7=9.3