【劉秉欣】評論
題目應該修改為電流增益 Io/IiIi = ib(RB+rb)
【謝旻融】評論
Ib=Ii*[RB/(RB+rb)]Ii=Ib/[RB/(RB+rb)]-------(A)Ic=β*Ib | *Io=-IcIo/Ii= -β*Ib/(A) = -β*[RB/(Rb+rb)]
