問題詳情

60. The Balmer series for the hydrogen atom corresponds toelectronic transitions that terminate in the state with quantumnumber n = 2 as shown in the figure. Consider the photon ofthe longest wavelength corresponding to a transition shown.What is its wavelength?


(A) 420 nm
(B) 458 nm
(C) 540 nm
(D) 656 nm
(E) 720 nm

參考答案

答案：D
難度：計算中-1
書單：沒有書單，新增

用户評論

【面試倒楣鬼-22幸運上後西】評論

最長的波長=能量最少的躍遷,在此是從n=3跳到n=2 (~1.9eV的),然後再用方便的 1240/eV或nm公式=> 1240/1.9 ~=650nm (D)如果不確定也可以帶入另一個躍遷極值算算看(n=∞->n=2),在此1240/3.4~=365nm, 無選項可選