【用戶】Ihou Vivian
【年級】高二上
【評論內容】n[ log(3*2^2) - 1] ≥ log2......我懂12=3*2^2,但不懂為什麼要-1-1 因為 (log12/10)=log12 - log10 = log12 - 1n[2 log2 + log3 -1] ≥ log2......「2 log2 + log3」這個是怎麼來的? log a*b =log a + log blog a^n =2 log an ≥ 0.301/(2*0.301+0.4771-1)=3.81......「0.301/(2*0.301+0.4771-1)」這又怎麼來的?log 2 =0.3010 log 3 =0.4771 代入計算log7=0.8451 最基本的這三個値要背起來,n最小 4 (n要整數所以最小4) 感謝信欣茗