問題詳情

31. Please order the following coenzymes according to their sequential involvement in the pyruvatedehydrogenase complex. Ⅰ.NAD+
Ⅱ.COA-SH Ⅲ.TPP IV. Lipoate (lipoamide) V. [FAD]
(A) III, II, I, IV, V
(B) III, II, I, V, IV
(C)III, IV, II, V, I
(D) II, IV, V, I, II
(E) III, V, IV, II, I 

參考答案

答案：C
難度：計算中-1
書單：沒有書單，新增

用户評論

【用戶】加油(邀請:154179)

【年級】大一下

【評論內容】Ⅲ. TPPIV. Lipoate (lipoamide)Ⅱ. COA-SHV. [FAD]Ⅰ. NAD+(C) III, IV, II, V, I。詳解:＊丙酮酸氧化為乙醯輔酶A:pyruvate+TPP → CO2+hydroxyethyl-TPPpyruvate氧化；TPP還原成hydroxyethyl-TPP(酵素:pyruvate dehydrogenase E1，產生1個CO2)hydroxyethyl-TPP+lipoamide → TPP+acetyl-dihydrolipoamidehydroxyethyl-TPP氧化成TPP；lipoamide還原成acetyl-dihydrolipoamide(酵素:dihydrolipoyl transacetylase E2)acetyl-dihydrolipoamide+CoA → dihydrolipoamide+acetyl-CoAacetyl-dihydrolipoamide轉變成dihydrolipoamide，並釋出acetyl-CoA(酵素:dihydrolipoyl transacetylase E2)dihydrolipoamide+FAD‧S-S → lipoamide+FAD‧SH SHdihydrolipoamide氧化成lipoamide；FAD‧S-S還原成FAD‧SH SH(酵素:dihydrolipoyl transacetylase E2)FAD‧SH SH + NAD+ → FAD‧S-S +  NADH+H+FAD‧SH SH氧化成FAD‧S-S；NAD+還原成NADH+H+(酵素:dihydrolipoyl dehydrogenase E3，產生1個NADH)pyruvate有2個，故可以產生2個NADH。 ＊丙酮酸去氫酶複合體(pyruvate dehydrogenase complex)生化反應參與酵素輔酶形式組成維生素脫羧基反應pyruvate dehydrogenaseTPP(thiamine pyrophosphate)維生素B1(thiamine)轉醯基反應dihydrolipoyl transacetylaselipoate(硫辛酸=擬脂酸)lipoic acid(硫辛酸=擬脂酸)CoA～SH  (Coenzyme A)泛酸(pantothenic acid)氧化還原反應dihydrolipoyl dehydrogenaseFAD(flavin adenine dinucleotide)維生素B2(riboflavin)NAD+(nicotinamide adenine dinucleotide)維生素B3=菸鹼素(niacin)＊丙酮酸經過去羧作用後的基團接在打斷雙硫鍵的lipoic acid 硫原子上，進行轉乙醯基生成Acetyl CoA。