82. Using the data shown as follows to calculate ΔG° for the reaction (1 F = 96,485 coulombs):Fe(s) + Cu2+(aq) → Fe2+(aq) + Cu(s). The reduction potentials for Fe2+and Cu2+are as follows:
Fe2+ + 2e– → Fe ε° = –0.44 V
Cu2+ + 2e– → Cu ε° = 0.34 V
(A) –1.9 × 104J
(B) –1.5 × 105J
(C) 0 J
(D) 1.9 × 104J
(E) 1.5 × 105J