【用戶】陳益華
【年級】國二上
【評論內容】H+: 0.05*0.02 = 0.001OH-: 0.05 * 0.03 = 0.00150.0015-0.001 = 0.0005 mol0.0005 mol / 0.05L =10^-2 [OH-]10^-14 / 10^-2 = 10^-12 [H+]所以 PH值 = 12
【用戶】陳益華
【年級】國二上
【評論內容】H+: 0.05*0.02 = 0.001OH-: 0.05 * 0.03 = 0.00150.0015-0.001 = 0.0005 mol0.0005 mol / 0.05L =10^-2 [OH-]10^-14 / 10^-2 = 10^-12 [H+]所以 PH值 = 12