【用戶】olivine
【年級】高三上
【評論內容】pH = pKa + log([A-]/[HA])(a)pH = -log(1.8*10^-5) + log(0.1/0.1) = 4.74(b) CH3COOH + NaOH → CH3COONa + H2O反應前 0.3 0.1反應後 0.2 0 0.1pH = -log(1.8*10^-5) + log(0.1/0.2) = 4.44(c) HCl + CH3COONa → CH3COOH + NaCl反應前 0.1 0.3反應後 0 0.2 0.1pH = -log(1.8*10^-5) + log(0.2/0.1...