【用戶】Jiunndar Yeh
【年級】幼兒園下
【評論內容】解法1:進行長除法 23 -27 1 +1 ) 23 -4 +k 23 +23 -27 +k -27 -27 k + 27由於23x2 - 4x + k可被x + 1整除故k + 27 = 0 ⇒ k = -27 ...選項(C)正確解法2:因23x2 - 4x + k可被x + 1整除故可分解23x2 - 4x + k = (x + 1) * (Ax + B)當x + 1 = 0時,原方程式會等於0, 此時 x = -1⇒ 23x2 - 4x + k = 23 * (-1)2 - 4 * (-1) + k = 23 + 4 + k = 27 + k = 0故 k = -27 ...選項(C)正確