【用戶】Kai
【年級】高一下
【評論內容】首先要先釐清每杯溶液中剩下什麼離子,再由此推論pH值。(A)有NH3 和 NH4+,[OH-]=1.8×10–5*1/1.5=1.2×10–5 M,pH=14-4.92=9.08(B)有NH3 和 NH4+,[OH-]=1.8×10–5*1.5/1=2.7×10–5 M,pH=14-4.57=9.43(C)有C5H5N and C5H6N+,[OH-]=1.7×10–9*1/1.5=1.13×10–9 M,pH=14-8.95=5.05(D)有C5H5N and C5H6N+,[OH-]=1.7×10–9*1.5/1=2.55×10–9 M,pH=14-8.59=5.41
【用戶】Kai
【年級】高一下
【評論內容】首先要先釐清每杯溶液中剩下什麼離子,再由此推論pH值。(A)有NH3 和 NH4+,[OH-]=1.8×10–5*1/1.5=1.2×10–5 M,pH=14-4.92=9.08(B)有NH3 和 NH4+,[OH-]=1.8×10–5*1.5/1=2.7×10–5 M,pH=14-4.57=9.43(C)有C5H5N and C5H6N+,[OH-]=1.7×10–9*1/1.5=1.13×10–9 M,pH=14-8.95=5.05(D)有C5H5N and C5H6N+,[OH-]=1.7×10–9*1.5/1=2.55×10–9 M,pH=14-8.59=5.41