【lisa860105】評論
HCl=5*10-4mol設加入a ml的NaOH=2a*10-5mol[H+]=1000[(nHCl-nNaOH)/(VHCl+VNaOH)] =1000[(5*10-4-2a*10-5)/(50+a)] =10-3=> 5*10-4-2a*10-5=(50+a)*10-6=> 500-20a=50+a=> a=450/21=21.4