【用戶】Neng Kuan Lin

【年級】小一上

【評論內容】F[s]=k/s*e -0s-2k/s*e-as+k/s*e-2as-.....周期T=2a,周期函數拉式轉換公式 £[f(t)]=[1/1-e-Ts]*F(s)£[f(t)]=1/(1-e-2as)*(k/s-(2k/s)*e-as+(k/s)*e-2as)        =k/s*1/(1-e-2as)*(1-2e-as+e-2as).........k/s提出來; a2-2ab+b2=(a-b)2        =k/s*[1/(1+e-as)(1-e-as)]*(1-e-as)2.....a2-b2=(a+b)(a-b)        =k/s*(1-e-as)2/(1+e-as)(1-e-as)............上下約掉(1-e-as)        =k(1-e-as)/s(1+e-as...

【用戶】Neng Kuan Lin

【年級】小一上

【評論內容】F[s]=k/s*e -0s-2k/s*e-as+k/s*e-2as-.....周期T=2a,周期函數拉式轉換公式:  £[f(t)]=F(s)*[1/1-e-Ts]£[f(t)]=[k/s-(2k/s)*e-as+(k/s)*e-2as]/(1-e-2as)        =k/s*[(1-2e-as+e-2as)/(1-e-2as)].........k/s提出 ;下一行分子 a2-2ab+b2=(a-b)2        =k/s*[(1-e-as)2/(1+e-as)(1-e-as)] ....上一行分母 a2-b2=(a+b)(a-b)        =k/s*(1-e-as)/(1+e-as...