295　若材料的蒲松氏比(Poisson’s ratio)為0.25，則彈性係數E與體積彈性係數K之關係為 (A)E = 2K (B)E = 1.5K (C)E = K (D)E = 0.5K

問題詳情

295　若材料的蒲松氏比(Poisson’s ratio)為0.25，則彈性係數E與體積彈性係數K之關係為
(A)E = 2K
(B)E = 1.5K
(C)E = K
(D)E = 0.5K　

答案：B
難度：適中0.615385
統計：A(0),B(8),C(2),D(2),E(0)